Bo & Allie
In trying to determine the possible color results of a breeding it can be important to know not only the sire and dam's colors, but also the colors of their parents and the colors of any puppies they may have already produced


Bo - Elysian Like the Night (solid blue) - sire = red & dam = black and white - we can expect from this that Bo carries a red/fawn and a white spotting gene

  

 

Allie - Coggeshall As Always (white and red) - sire = fawn and white & dam = fawn - this conveys no further information than we already know from Allie's visible color and pattern

 

 

Note: yellow, red and fawn are "lumped" together genetically

Bo and Allie were bred together 2 times
 1st litter: (10 puppies)  2nd litter: (10 puppies)
1 black - solid 1 black - solid
4 black and white - all Irish Marked
1 blue and white - Irish Marked 1 blue and white - Irish Marked
3 red or fawn and white - all Irish Marked 4 red or fawn and white - all Irish Marked
1 red with black mask - solid red  2 reds - solid
  1 blue fawn - solid
   1 blue fawn and white - Irish Marked

A locus
We already know that Allie is a red and the presence of the red and fawn puppies tells us that Bo carries the gene for that color as expected. So we have:

Bo = AyAy (pure for red/fawn)
Allie = AyAy (pure for red/fawn)

C locus
Bo is not described as a light blue, nor is Allie a pale fawn, and none of the puppies is described as pale - so we will assume the following:

Bo = CC (pure for complete expression of red/yellow and blue pigments)
Allie = CC (ditto)

D locus
We already know the Bo is blue and the presence of the blue and blue fawn puppies tells us that Allie carries that gene, but does not display it in her own color. So we now have:

Bo = dd (pure for blue)
Allie = Dd (dominant for normal color and carrying blue)

E locus
Because Bo is solid blue we can't see a mask and we know that Allie does not display a mask, but the presence of the black-masked red puppy tells us that the gene exists and we can assume Bo contributed it and the presence of the red and fawn puppies without a mask shows that he is not pure for the mask. So now we have:

Bo = EEm (expresses dark pigment and carries the mask)
Allie = EE - (pure for expression of dark pigment)

K locus
Because Bo is solid blue we know he is genetically black and must carry that gene, but since there were red/fawn puppies we know he is not pure for black. Allie is not black or blue, so does not carry that gene. Since there were no brindles, we know that neither parent carried that gene.

Bo = Kk (expresses dark pigment, carryies red/fawn)
Allie = kk (pure for red/fawn

R locus
Since neither the parents nor any of the puppies are described as Roan we will assume the following:

Bo = rr (displays normal color and does not carry Roan)
Allie = rr (ditto)

S locus
We already know that Allie displays white and Bo does not, but the presence of the parti-colored puppies shows that Bo carries the gene for more white than he displays as expected, and since all the puppies with white are described as Irish Marked we know that this is the gene he carries. So now we know:

Bo = Ssi (solid in his own color, carrying Irish Marked white)
Allie = spsp (probably pure for parti-color)

T locus
Not enough data to tell.


All of this gives us the following analysis of the color genetics involved with these parents and their offspring:

Bo - Elysian Like the Night - solid blue = AyAy CC dd EEm Kk rr Ssi
Allie - Coggeshall As Always - white and red = AyAy CCDd EE kk rr spsp

Genetic notation is simply a "short-hand" method of conveying information about the genes carried and/or displayed.  Dominant genes are noted as UPPERCASE and are listed first at each locus, when they are present. Recessive genes are noted as lower case and are listed second at each locus, when a dominant is present.  In the case of 2 dominants or 2 recessives at the same locus the one that is dominant over it's locus partner is listed first. Superscript letters provide futher description of the particular gene's actions.  The above examples convey quick information about what colors these parents can be expected to produce:

Bo = AyAy CC dd EEm Kk rr Ssi

AyAy = pure for red/fawn, but this color is not displayed on the dog because the presence of the "K" gene hides it's expression
CC = full expression of pigment, not "washed out" in shade
dd = pure for blue dilution of black, this gene is visibly expressed because the "K" gene allow expression of black and this gene then acts to
......alter the shade of color from black to blue
E = allows expression of the black/blue provided by the action of the "K" and "dd" genes
Em = same as for the "E" gene, but allows the further expression the "mask" pattern - in Bo the action of this gene is not visible because it is ......impossible to distinguish a blue mask on a solid blue dog
K = allows expression of black
k = carrying non-black
rr = not Roaned
S = solid color with no white
si = because Bo is solid we know that he himself exhibits the "S" gene, but since he contributed to the production of several Irish Marked ......puppies he carries the Irish Marked gene and since Allie is more white than red, and since "more white is more recessive" the Irish Marking ......could not have come from her

Allie = AyAyCCDdEErrspsp

AyAy = pure for red/fawn, since Allie is neither blue nor black she cannot carry the "A" gene as Bo does
CC = full expression of pigment, not "washed out" in shade
D = full expression of dark color, but since Allie is a clear red with no apparent black hairs this gene has no pigment on which to act
d = Allie does not express this gene, as it's action is inhibited by the presence of the dominant "D" gene, but we know she carries it as she ......produced several blue or blue fawn puppies
EE = allows the expression of dark pigment, but since Allie is pure for fawn at the A locus she has no dark pigment to display
kk = pure for red/fawn
rr = not Roaned
spsp = parti-colored with more or less equal amounts of white and fawn.  Since all of Allie's puppies that display white are described as Irish ......Marked they must have inherited the gene from Bo, and Allie's "sp" contribution is inhibited by the action of the "si" gene contributed by Bo


The puppies genetics will be:

solid black = AyAy CC Dd EE or EEm Kk rr Ssp
solid blue = AyAy CC dd EE or EEm Kk rr Ssp
solid fawn or red = AyAy CC Dd EE kk rr Ssp
solid fawn or red, black mask = AyAy CC Dd EEm kk rr Ssp
solid blue fawn = AyAy CC dd EE kk rr Ssp
black and white (Irish Marked) = AyAy CC Dd EE Kk rr sisp
blue and white (Irish Marked) = AyAy CC dd EE Kk rr sisp
fawn or red and white (Irish Marked) = AyAy CC Dd EE kk rr sisp
blue fawn and white (Irish Marked) = AyAy CC dd EE kk rr sisp

All of Bo and Allie's puppies will carry blue, since Bo has no other gene to contribute at that locus. Also, they will all carry white spotting and fawn as Allie has no other genes to contribute for those locations.

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