What you CAN'T get (see below for white):

 If BOTH parents are:  you can't get:
black

K(K/kbr/k)
x
K(K/kbr/k)

fawns & brindles in the same litter

because each parent can only carry 1 other gene at the K locus they can only produce one other color besides black.

blue (solid, fawn, or brindle)

dd x dd

black pigment or coat

because there is no dominant D gene 2 blues cannot produce black pigment or coat color

brindle

ayaykbr(kbr/k)
x
ayaykbr(kbr/k)

solid blacks or blues

because there is no dominant K gene 2 brindles cannot produce solid blacks or blues

fawn

ayayEm(Em/E/e)kk
x
ayayEm(Em/E/e)kk

brindle

because there is no brindle (kbr) gene 2 fawns cannot produce brindles

ayayEm(Em/E/e)kk
x
ayayEm(Em/E/e)kk

solid black or solid blue (*see Note below)

because there is no dominant K gene 2 fawns cannot produce solid blacks or blues

 If parents are:  you can't get:
brindle x fawn

ayaykbr(kbr/k)
x
ayaykk

solid blacks or blues

because there is no dominant K gene a fawn and brindle cannot produce solid blacks or blues

 *Note: EXCEPT if one parent has absolutely NO black hairs then that dog might be a fawn produced by the double "ee" recessive and such a fawn CAN produce a solid black or blue (if the dog is a genetic black or blue) when bred to a normal fawn

 White - what you CAN"T get:

NOTE: in white markings the action of plus (+) and minus (-) modifiers cause some overlap of visible markings, so take these as generalizations - not absolutes!

 If BOTH parents are:  you can't get:
solid

S(si /sp/sw)
x
S(si /sp/sw)

solids & Irish marked & parti-color & extreme white

because there are 4 genes at the S locus, these 2 parents cannot produce all 4 patterns

Irish marked

si (si /sp/sw)
x
si (si /sp/sw)

solids, or Irish marked & parti-color & extreme white

because there are 2 other genes recessive to Irish marked, 2 parents cannot produce all 3 patterns. Solids are excluded by the absence of the dominant Solid gene

Parti-color

sp(sp/sw)
x
sp(sp/sw)

solids or Irish marked

Solids and Irish marked are excluded by the absence of the genes for these patterns

Extreme White

swsw
x
swsw

solids, or Irish marked, or parti-color

Solids and both Irish marked and parti-color are excluded by the absence of the genes for these patterns

 If parents are: you can't get:
solid x
Irish marked

S(si /sp/sw)
x
si (si /sp/sw)

Irish marked & parti-color & extreme white

because there are 3 white-pattern genes at the S locus, these 2 parents cannot produce all 3 patterns in one litter

solid x parti-color

S(si /sp/sw)
x
sp(sp/sw)

Irish marked & parti-color & extreme white

Because there are 3 other genes at this locus, these 2 parents cannot produce all 3 patterns in one litter

solid x
extreme white

S(si /sp/sw)
x
swsw

Irish marked & parti-color & extreme white

because there are 3 other genes at this locus these 2 parents cannot produce all 3 patterns in one litter

Irish marked x parti-color

si (si /sp/sw)
x
sp(sp/sw)

solids, or parti-color & extreme white

solids are excluded by the absence of the solid gene. Because there are 3 other genes at this locus, these 2 parents cannot produce all 3 patterns in one litter

Irish marked x extreme white

si (si /sp/sw)
x
swsw

solids, or parti-color & extreme white

solids are excluded by the absence of the solid gene. Because there are 3 other genes at this locus, these 2 parents cannot produce all 3 patterns in one litter

parti-color x extreme white

sp(sp/sw)
x
swsw

solids or Irish marked

solids are excluded by the absence of the solid gene. Irish marked is excluded by the absence of the gene for this pattern.

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